DHARM
772 GEOTECHNICAL ENGINEERING
determine the minimum thickness of the seal required. Check for perimeter shear also.
Assume σc = 2400 kN/m^2 and γc = 24 kN/m^3 , for concrete. Allowable perimeter shear stress
= 650 kN/m^2.
Solution:
Referring to Fig. 19.8,
H = 20 – 2 = 18 m
From Eq. 19.6,
q = (γwH – γct)
t being the thickness of concrete seal.
∴ q = (10 × 18 – 24t)
From Eq. 19.4,
t = 059.D
q
i
σc
Squaring, t^2 = (0.59)^2 (6)^2 ×
()180 24
2400
− t
1.8 m
33 m
Concrete
seal
2.4 m
6.0 m
Fig. 19.7 Open Caisson (Ex. 19.1)
or t^2 + 0.125t – 0.940 = 0
or t = 0.91 m
t may be taken as 1 m.