DHARM774 GEOTECHNICAL ENGINEERING
Ht. of centre of buoyancy, B, above the baseAB=545
2.
= 2.725 mAG is given as 4.200 m
∴ BG = 4.200 – 2.725 = 1.475 mBM(M being the Metacentre) =I
V
=1
1218 9^1
882 35×××^3
.= 1.240 m∴ AM=+AB BM = 2.725 + 1.240 = 3.965 mAG being 4.200 m, M is below G, and the metacentric height MG is negative (the nu-
merical value of MG is 0.235 m). The caisson is, therefore, unstable.
The caisson can be made stable by filling it with, say, sand ballast (Assume γsand = 22
kN/m^3 ).
Let us try a thickness of 0.5 m of sand.
The height of the new centre of gravity, G′, above the baseAG′ =9000 4 2 9 18 0 5 22 0 25
9000 9 18 0 5 22×+××××
+× × ×...
(.)m= 3.55 m9m10 m
GA4.2 mFig. 19.9 Stability of box caisson (Ex. 19.3)New depth of immersion, d′ =()
.9000 1782
10 2 9 18+
×× = 6.525 m(^) AB′=6 525
2
. m = 3.263 m
BM I V′′= = × × ×
××/(/)
.112 18 91
9 18 6 525(^3) m = 1.035 m
AM′=AB′+ ′ ′B M = 3.263 + 1.035 = 4.298 m
Since AM′>AG′, M′ is above G′( ...MG′′=4 298 3 550 0 748 m)− =. Since M′ is above G′,
the metacentric height M′G′ being positive, the caisson is stable.