DHARM
774 GEOTECHNICAL ENGINEERING
Ht. of centre of buoyancy, B, above the base
AB=
545
2
.
= 2.725 m
AG is given as 4.200 m
∴ BG = 4.200 – 2.725 = 1.475 m
BM(M being the Metacentre) =
I
V
=
1
12
18 9^1
882 35
×××^3
.
= 1.240 m
∴ AM=+AB BM = 2.725 + 1.240 = 3.965 m
AG being 4.200 m, M is below G, and the metacentric height MG is negative (the nu-
merical value of MG is 0.235 m). The caisson is, therefore, unstable.
The caisson can be made stable by filling it with, say, sand ballast (Assume γsand = 22
kN/m^3 ).
Let us try a thickness of 0.5 m of sand.
The height of the new centre of gravity, G′, above the base
AG′ =
9000 4 2 9 18 0 5 22 0 25
9000 9 18 0 5 22
×+××××
+× × ×
...
(.)
m
= 3.55 m
9m
10 m
G
A
4.2 m
Fig. 19.9 Stability of box caisson (Ex. 19.3)
New depth of immersion, d′ =
()
.
9000 1782
10 2 9 18
+
×× = 6.525 m
(^) AB′=6 525
2
. m = 3.263 m
BM I V′′= = × × ×
××
/(/)
.
112 18 9
1
9 18 6 525
(^3) m = 1.035 m
AM′=AB′+ ′ ′B M = 3.263 + 1.035 = 4.298 m
Since AM′>AG′, M′ is above G′( ...MG′′=4 298 3 550 0 748 m)− =. Since M′ is above G′,
the metacentric height M′G′ being positive, the caisson is stable.