DHARMELEMENTS OF SOIL DYNAMICS AND MACHINE FOUNDATIONS 867
Example 20.9: Obtain the velocity of the tup of a forge hammer before impact and that of the
anvil after impact, given the following:
weight of the tup and die = 15.50 kN
stroke of tup = 900 mm
weight of anvil and frame = 342 kN
efficiency of drop = 0.9
coefficient of restitution = 0.5
steam pressure = 700 kN/m^2
area of piston = 0.129 m^2
Determine the amplitudes of vibration of the foundation and anvil if the limiting natu-
ral frequency of the anvil is 253 rad/s, and the two natural frequencies of the combined system
are 272 rad/s and 54.3 rad/s.
Since stream pressure is given, this is a double-acting hammer.
The correction factor, α = 0.9 (the efficiency of drop).
Velocity of the tup before impactv = α2 gW pah
Wt
t(.)+Substituting α = 0.9, Wt = 15.50 kN, p = 700 kN/m^2 , a = 0.129 m^2 , and h = 900 mm
= 0.9 m,
We havev = 092 9 81 15 50 700 0 129 0 9
15 50..(.. ).
.×+××
m/s= 9.88 m/s
Velocity of anvil after impactva =()
()1
1+
+e
v
λawhere λa =M
MW
Wa
ta
t==342
15 5.= 22.06Substituting e = 0.5, λa = 22.06, and v = 9.88 m/s,we have
va =(.)
(.).105
12206988+
+× = 0.643 m/sAmplitude of the vibration of the foundationA 1 = –()()
()ωωωω
ωω ω ωanan
an n nva2
222
12
2
12
22
2−−
−
Substituting ωa = 253 rad/s, ωn 1 = 272 rad/s, ωn 2 = 54.3 rad/s,and va = 0.643 m/s,
A 1 = –(.)( )
(.)..253 54 3 253 272
253 272 54 3 54 30 6432222
22 3−−
−× m = 1.58 mm