DHARM
ELEMENTS OF SOIL DYNAMICS AND MACHINE FOUNDATIONS 867
Example 20.9: Obtain the velocity of the tup of a forge hammer before impact and that of the
anvil after impact, given the following:
weight of the tup and die = 15.50 kN
stroke of tup = 900 mm
weight of anvil and frame = 342 kN
efficiency of drop = 0.9
coefficient of restitution = 0.5
steam pressure = 700 kN/m^2
area of piston = 0.129 m^2
Determine the amplitudes of vibration of the foundation and anvil if the limiting natu-
ral frequency of the anvil is 253 rad/s, and the two natural frequencies of the combined system
are 272 rad/s and 54.3 rad/s.
Since stream pressure is given, this is a double-acting hammer.
The correction factor, α = 0.9 (the efficiency of drop).
Velocity of the tup before impact
v = α
2 gW pah
W
t
t
(.)+
Substituting α = 0.9, Wt = 15.50 kN, p = 700 kN/m^2 , a = 0.129 m^2 , and h = 900 mm
= 0.9 m,
We have
v = 09
2 9 81 15 50 700 0 129 0 9
15 50
.
.(.. ).
.
×+××
m/s
= 9.88 m/s
Velocity of anvil after impact
va =
()
()
1
1
+
+
e
v
λa
where λa =
M
M
W
W
a
t
a
t
==
342
15 5.
= 22.06
Substituting e = 0.5, λa = 22.06, and v = 9.88 m/s,
we have
va =
(.)
(.)
.
105
12206
988
+
+
× = 0.643 m/s
Amplitude of the vibration of the foundation
A 1 = –
()()
()
ωωωω
ωω ω ω
anan
an n n
va
2
2
22
1
2
2
1
2
2
2
2
−−
−
Substituting ωa = 253 rad/s, ωn 1 = 272 rad/s, ωn 2 = 54.3 rad/s,
and va = 0.643 m/s,
A 1 = –
(.)( )
(.).
.
253 54 3 253 272
253 272 54 3 54 3
0 643
2222
22 3
−−
−
× m = 1.58 mm