DHARM76 GEOTECHNICAL ENGINEERINGPercentage error = (2.694 2.500)
2.694−
× 100 = 7.2.Example 3.5: A pyknometer was used to determine the water content of a sandy soil. The
following observation were obtained:
Weight of empty pyknometer = 8 N
Weight of pyknometer + wet soil sample = 11.60 N
Weight of pyknometer + wet soil + water filling remaining volume = 20 N
Weight of pyknometer + water = 18 N
Specific gravity of soil solids (determined by a separate test) = 2.66
Compute the water content of the soil sample.
The weights may be designated W 1 through W 4 in that order,
By Eq. 3.6,
w =()
()WW
WWG
G21
341
1−
−F −
HGI
KJ−L
NM
O
QP × 100
Substituting the values,w =(11.60 8.00)
(20 18)(2.66 1)
2.66− 1
−× − −L
NM
O
QP × 100
=3.6
2.01.66
2.66L ×− 1
NMO
QP× 100= (1.1233 – 1) × 100 = 12.33
∴ Water content of the soil sample = 12.33%.Example 3.6: A soil sample with a grain specific gravity of 2.67 was filled in a 1000 ml con-
tainer in the loosest possible state and the dry weight of the sample was found to be 14.75 N. It
was then filled at the densest state obtainable and the weight was found to be 17.70 N. The
void ratio of the soil in the natural state was 0.63. Determine the density index in the natural
state.
G = 2.67
Loosest state:
Weight of soil = 14.75 NVolume of solids = 14.75
0.0267cm^3 = 552.4 cm^3Volume of voids = (1000 – 552.4) cm^3 = 447.6 cm^3
Void ratio, emax = 447.6/552.4 = 0.810
Densest state:
Weight of soil = 17.70 NVolume of solids =17.70
0.0267cm^3 = 662.9 cm^3Void ratio, emin =337.1
662.9= 0.508