Uniform Series Compound Interest Formulas 87
Looking at Figure 4-1, we see that if an amountAis investedat the end of each year for
4 years, the total amountFat the end of 4 years will be the sum of the compound amounts
of the individual investments.
A A A A A A A A
+ + + + + ..q'-- -+ + +
0-1-2-3-4=0-1-2-3-4+0-1-2-3-4+0-1-2-3-4+0-1-2-3-4
1 1 ~ t
F A(l +i)3 + A(l +i)2 + A(l +i) + A
In the general case fornyears,
F=A(1+i)n-l+ ... +A(1+i)3+A(1+i)2+A(1+i)+A (4-1)
Multiplying Equation (4-1) by (1 +i),we have.
(1 +i)F =A(1+i)n+... +A(1+i)4
- A(1+i)3+A(1+i)2+A(1+i) (4-2)
Factoring outAand subtracting Equation 4-1 gives
(4-3)
(4-4)
Solving Equation 4-4 forFgives
[
(1 +i)n- 1
]
.
F=A i =A(F/A,z%,n)
(4-5)
Thus we have an equation forFwhenAis known. The term inside the brackets
is called theuniformseriescompound amount factorand has the notation(F/A, i,n).
A man deposits $500 in a credit union at the end of each yearfot5 years. The credit union pays
5% interest, compounded annually.At the end of 5 years, immediately after the fifth deposit, how
much does the man have in his account?