Engineering Economic Analysis

(Chris Devlin) #1

118 MORE INTERESTFORMULAS


I....
9V!)- .:~ <-. .~..-~

How long will it take for money to double at 10% nominal interest, compounded continuously?


F=Pern


2 = 1 eO.IOn

eO.IOn = 2
or

O.lOn= 102 = 0.693


n= 6.93 years


It will take 6.93 years for money to double at 10% noniinal interest, compounded continuously.


If the savings bank in Example 4-14 changed its interest policy to 6% interest, compounded
continuously, what are the nominal and the effectiveinterest rates?


  • SOLUTION


The nominal interest rate remains at 6% per year.


Effective interest rate=er- 1


=eO.06- 1 =0.0618

=6.18%
..:.

Uniform Payment Series: Continuous Compounding
at Nominal Raterper Period
Let us now substitute the equation i=er- 1 into the equations for end-of-period
compounding.

Continuous Compounding Sinking Fund
er-1
[AI F, r, n]=ern _ 1 (4-41)

Continuous Compounding Capital Recovery
ern(er- 1)
[AlP, r,n]= ern- 1 (4-42)

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