118 MORE INTERESTFORMULAS
I....
9V!)- .:~ <-. .~..-~
How long will it take for money to double at 10% nominal interest, compounded continuously?
F=Pern
2 = 1 eO.IOn
eO.IOn = 2
or
O.lOn= 102 = 0.693
n= 6.93 years
It will take 6.93 years for money to double at 10% noniinal interest, compounded continuously.
If the savings bank in Example 4-14 changed its interest policy to 6% interest, compounded
continuously, what are the nominal and the effectiveinterest rates?
- SOLUTION
The nominal interest rate remains at 6% per year.
Effective interest rate=er- 1
=eO.06- 1 =0.0618
=6.18%
..:.
Uniform Payment Series: Continuous Compounding
at Nominal Raterper Period
Let us now substitute the equation i=er- 1 into the equations for end-of-period
compounding.
Continuous Compounding Sinking Fund
er-1
[AI F, r, n]=ern _ 1 (4-41)
Continuous Compounding Capital Recovery
ern(er- 1)
[AlP, r,n]= ern- 1 (4-42)
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