Ideas of Chance in Computer Science 479Example 2. Suppose Q2 = {0, 1}. Then, 0 and 1 are the outcomes. Here, 0 might represent
the outcome that a communication line is busy and 1 that the line is free. The experiment
might be to check the status of the line. Four events are associated with Q2-namely, 0, {0},
{1}, and {O, 1). The event E = {0, 1} always occurs, because the line is always either busy
or free. 0Example 3. Suppose Q2 is the set of positive integers. Then, each positive integer is an
outcome. This sample space might be used when the experiment is to flip a coin until it
comes up heads. The outcome is the number of flips. The set
E = {2 n : n is a positive integer}expresses the event of an even number of flips. U
Definition 4. A probability density p on a discrete sample space Q2 is a function with
domain Q2 satisfying
For eachwE Fo eaho E 02, ,)^0 < p ((o) < 1,n 1, and Y, p (0)) =I1.
(OEQ
Any function satisfying these properties is, mathematically speaking, a legitimate
probability density function. The value of the probability density function on an outcome
is the probability of the outcome.
In the dice-rolling experiment, suppose that the sample space Q2 is chosen to be
Q I = 12,3,4, 5,6,7, 8,9, 10, 11, 121
Then, the following function on Q1 is a legitimate probability density function:
1
p(2) = p(12) = 362p(3) = p(ll) =
36
3
p(4) = p(10) =- 364
p(5) = p(19) = 365
p(6) = p(18) =
36
6
p(7) = - 36Clearly, p(w) > 0 for each outcome, and the sum of the probability density function over
all the outcomes is 1. Hence, the two requirements of Definition 4 are satisfied.
Definition 5. Let E be an event in a sample space Q2 endowed with a probability density
function p(wo). If E 0 0, the probability P (E) of event E is
P(E) = YP(a)
wc E