ShearMoment
(m)0.5774lR 1R 1 =V 1R 2 =V2maxMmax∆max∆xatx = = 0.5774lVxMxR 2V 1l
xWMmaxV 2=
W
3W
3=^2 W
3
==W
3- Wx^2
l^2
(l^2 – x^2 )Wl^2
EI== 0.01304(3x^4 – 10l^2 x^2 + 7l^4 )
Wx
180 EIl^2=Wx
3 l^22 Wl = 0.1283Wlatx = l 1 –^8 = 0.5193l
159 336
FIGURE 2.3 Elastic-curve equations for prismatic beams. (m) Simple beam—load increasing uniformly to one end.
(Continued)