250 MATHEMATICS
Solution : The volume of water in the overhead tank equals the volume of the water
removed from the sump.
Now, the volume of water in the overhead tank (cylinder) = r^2 h
= 3.14 ✁ 0.6 ✁ 0.6 ✁ 0.95 m^3The volume of water in the sump when full =l ✁ b ✁ h = 1.57 ✁ 1.44 ✁ 0.95 m^3
The volume of water left in the sump after filling the tank
= [(1.57 ✁ 1.44 ✁ 0.95) – (3.14 ✁ 0.6 ✁ 0.6 ✁ 0.95)] m^3 = (1.57 ✁ 0.6 ✁ 0.6 ✁ 0.95 ✁ 2) m^3
So, the height of the water left in the sump =
volume of water left in the sump
lb✂=1.57 0.6 0.6 0.95 2
m
1.57 1.44✄ ✄ ✄ ✄
✄
= 0.475 m = 47.5 cmAlso,
Capacity of tank
Capacity of sump=
3.14 × 0.6 0.6 0.95 1
1.57 × 1.44 × 0.95 2
✂ ✂
☎
Therefore, the capacity of the tank is half the capacity of the sump.
Example 10 : A copper rod of diameter 1 cm and length 8 cm is drawn into a wire of
length 18 m of uniform thickness. Find the thickness of the wire.
Solution : The volume of the rod =
2
(^1) 8cm (^33) 2 cm
2
✞✟✆ ✝ ✟ ✠ ✞
✡ ☛
☞ ✌
.
The length of the new wire of the same volume = 18 m = 1800 cm
If r is the radius (in cm) of cross-section of the wire, its volume = ✁ r^2 ✁ 1800 cm^3
Therefore, ✁ r^2 ✁ 1800 = 2
i.e., r^2 =
1
900
i.e., r =
1
30
So, the diameter of the cross section, i.e., the thickness of the wire is
1
15
cm,i.e., 0.67mm (approx.).
Example 11 : A hemispherical tank full of water is emptied by a pipe at the rate of
4
3
7
litres per second. How much time will it take to empty half the tank, if it is 3m in
diameter? (Take ✍ =