NCERT Class 10 Mathematics

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SURFACE AREAS AND VOLUMES 259


  1. Given a right circular cone, which is sliced through by a plane parallel to its base, when
    the smaller conical portion is removed, the resulting solid is called a Frustum of a Right
    Circular Cone.

  2. The formulae involving the frustum of a cone are:


(i) Volume of a frustum of a cone =  121222 ✁

1

3

✂hrrrr✄ ✄.

(ii) Curved surface area of a frustum of a cone = ☎l(r 1 + r 2 ) where l = hrr^2 ✞✆ 12 ✟ ✝^2.

(iii) Total surface area of frustum of a cone = ☎l(r 1 + r 2 ) + ☎(r 12 + r^22 ) where
h = vertical height of the frustum, l = slant height of the frustum
r 1 and r 2 are radii of the two bases (ends) of the frustum.
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