3-5 Sequential Reactions 101
SEQUENTIAL REACTIONS
Often more than one reaction is required to change starting materials into the desired
product. This is true for many reactions that we carry out in the laboratory and for many
industrial processes. These are called sequential reactions.The amount of desired prod-
uct from each reaction is taken as the starting material for the next reaction.
EXAMPLE 3-11 Sequential Reactions
At high temperatures, carbon reacts with water to produce a mixture of carbon monoxide, CO,
and hydrogen, H 2.
heat
CH 2 O8888nCOH 2
Carbon monoxide is separated from H 2 and then used to separate nickel from cobalt by
forming a gaseous compound, nickel tetracarbonyl, Ni(CO) 4.
Ni4CO88nNi(CO) 4
What mass of Ni(CO) 4 could be obtained from the CO produced by the reaction of 75.0 g of
carbon? Assume 100% yield.
Plan
We interpret both chemical equations in the usual way, and solve the problem in two steps.
They tell us that one mole of C produces one mole of CO and that four moles of CO is
required to produce one mole of Ni(CO) 4.
- We determine the number of moles of CO formed in the first reaction.
- From the number of moles of CO produced in the first reaction, we calculate the number
of grams of Ni(CO) 4 formed in the second reaction.
Solution
- C H 2 O88nCO H 2
1 mol 1 mol 1 mol 1 mol
12.0 g
__? mol CO75.0 g C6.25 mol CO
- Ni 4CO88nNi(CO) 4
1 mol 4 mol 1 mol
171 g
1 mol CO
1 mol C
1 mol C
12.0 g C
3-5
__? g Ni(CO) 4 6.25 mol CO267 g Ni(CO) 4
Alternatively, we can set up a series of unit factors based on the conversions in the reaction
sequence and solve the problem in one setup.
g C 88n mol C 88n mol CO 88n mol Ni(CO) 4 88n g Ni(CO) 4
__? g Ni(CO) 4 75.0 g C267 g Ni(CO) 4
You should now work Exercise 46.
171 g Ni(CO) 4
1 mol Ni(CO) 4
1 mol Ni(CO) 4
4 mol CO
1 mol CO
1 mol C
1 mol C
12.0 g C
171 g Ni(CO) 4
1 mol Ni(CO) 4
1 mol Ni(CO) 4
4 mol CO