Molality
The molality,m,of a solute in solution is the number of moles of solute per kilo-
gram of solvent.molalityEXAMPLE 14-1 Molality
What is the molality of a solution that contains 128 g of CH 3 OH in 108 g of water?
Plan
We convert the amount of solute (CH 3 OH) to moles, express the amount of solvent (water)
in kilograms, and apply the definition of molality.
Solution
37.0 mCH 3 OHYou should now work Exercise 28.
EXAMPLE 14-2 Molality
How many grams of H 2 O must be used to dissolve 50.0 grams of sucrose to prepare a 1.25 m
solution of sucrose, C 12 H 22 O 11?
Plan
We convert the amount of solute (C 12 H 22 O 11 ) to moles, solve the molality expression for kilo-
grams of solvent (water), and then express the result in grams.
Solution
_?_ mol C 12 H 22 O 11 50.0 g C 12 H 22 O 11 0.146 mol C 12 H 22 O 11molality of solutionRearranging gives
kg H 2 O0.117 kg H 2 O 117 g H 2 O0.146 mol C 12 H 22 O 11
1.25 mol C 12 H 22 O 11 /kg H 2 Omol C 12 H 22 O 11
molality of solutionmol C 12 H 22 O 11
kg H 2 O1 mol C 12 H 22 O 11
342 g C 12 H 22 O 1137.0 mol CH 3 OH
kg H 2 O1 mol CH 3 OH
32.0 g CH 3 OH128 g CH 3 OH
0.108 kg H 2 O_?_ mol CH 3 OH
kg H 2 Og CH 3 OH mol CH 3 OHg H 2 O kg H 2 Omolalitynumber of moles solute
number of kilograms solventMolality is based on the amount of
solvent not solution.14-8 Molality and Mole Fraction 555In other examples later in this chapter
we will calculate several properties of
the solution in Example 14-2.Each beaker holds the amount of a
crystalline ionic compound that will
dissolve in 100. grams of water at
100°C. The compounds are (top row,
left to right)39 grams of sodium
chloride (NaCl, white), 102 grams of
potassium dichromate (K 2 Cr 2 O 7 ,
red-orange), 341 grams of nickel
sulfate hexahydrate (NiSO 4 6H 2 O,
green); (bottom row, left to right)
79 grams of potassium chromate
(K 2 CrO 4 , yellow), 191 grams of
cobalt(II) chloride hexahydrate
(CoCl 2 6H 2 O, dark red), and
203 grams of copper sulfate
pentahydrate (CuSO 4 5H 2 O, blue).