116 5Cables
After that, the shape of the cable and internal forces in the cable may be defined
easily.
The special caseaD0:5lleads to the following results for thrust and sag
HD
P
2
q
l^20 1
;
fD
Pl
4H
D
l
2
q
l 02 1:
There are some interesting numerical results. Assume thatl 0 DLl D1:01.Inthis
casef D0:071 l, so if the total length of the cableLexceeds the spanlonly by
1%, then sag of the cable comprises 7% of the span.
5.2.2 Cable Subjected to Uniformly Distributed Load
Distributed load within the horizontal projection of the cable may be considered
for the case when the hangers (Fig.5.1) are located very often. Design diagram of
flexible cable under uniformly distributed load is presented in Fig.5.4.
Fig. 5.4 A cable under
uniformly distributed load
y
x
q
l
x
RB
H
RA
H
A
y(x)
B
5.2.2.1 Direct Problem
ThrustHof the cable is given. Determine the shape of the cable and calculate dis-
tribution of internal forces. For solving of this problem we will use two approaches.
1.Integration of fundamental equation of a flexible cable (5.8) leads to following
expressions for slope and shape of the cable
dy
dx
D
q
H
xCC 1 ;
yD
q
H
x^2
2
CC 1 xCC 2 :