118 5Cables
Therefore, the total lengthLof the cable in terms of sag according to (5.13) becomes
LDZl0s1 C
4f
l 2
2x
l 1 2
dx: (5.13a)Approximate Solution of Length Determination
The binomial theorem to expand radical in a seriesp
1 C"Š 1 C^12 "^18 "^2 C:::
allows presenting (5.13a) as follows:LDZl0(
1 C1
2
4f
l
2x
l 1 2
1
8
4f
l
2x
l 1 4
C:::)
dx: (5.15)Integration of this relation leads to the following approximate expression:
LDl"
1 C8
3
f
l 2
32
5
f
l 4
C256
7
f
l 6
:::#
(5.16)This expression allows calculating the sagfof the cable in terms of total lengthL
and spanl.SincefDql^2 =8H, then length of the cable in terms of thrustHmay
be presented as follows
LDl
1 C1
24q^2 l^2
H^21
640q^4 l^4
H^4C:::
(5.16a)This expression allows calculating thrustHin terms of spanl, total length of the
cableL,andloadq.
Gentile Cable
Iff < 0:1l, then a cable is called the gentile one. Taking into account two terms in
equation (5.16a), we get the following equation
LDl
1 C1
24q^2 l^2
H^2
(5.16b)Therefore, thrust in terms of total length of the cableLand spanlmay be presented
in the form
HDql
2p
61
p
l 0 1;l 0 DL
l: (5.16c)