Problems 267
RA
H
MA
RB
H
MB
l=2R
O
q
R
Fig. P7.22
Ans.RADqR ; HD0:56012qR; MAD0:10658qR^2
7.23.Design diagram of a two-hinged parabolic arch with the tie is presented in
Fig.P7.23. The equation of the neutral line of the arch is
4f = l^2
x.lx/.The
cross-sectional moments of inertia vary by lawIxDICcos'x.m^4 /. The flexural
stiffness in the highest section of the arch isEIC. The cross-sectional area of the tie
isAt.m^2 /. Modulus of elasticity of the material of the arch and the tie areE.kN=m^2 /
andEt, respectively. Calculate internal axial force in the tie.
y x
P=6m
xq= 12
x
q=2kN/m
f=6m
P=8kN
l=24m
EtAt
EIC
Fig. P7.23
Ans.X 1 D
8558:67
517:082C24ˇ
;ˇD
EIC
EtAt
.
7.24.A rigid horizontal weightless beam is supported by three identical vertical
rods at points 1-3. The beam supports a loadP, as shown in Fig.P7.24. The stiffness
EAis constant for all vertical rods. Determine the axial forces in members 1-3.
P
d d l
1 2 3
Fig. P7.24
Ans.N 1 D0:833PI N 2 D0:333PI N 3 D0:167P.