350 10 Influence Lines MethodTable 10.5 Calculation of IL
Q^0 k
LoadPD 1 is located to the left of
sectionk,.u 0:6/LoadPD 1 is located to the right
of sectionk.u 0:6/
Point u Q^0 kDRP Point u Qk^0 DR
1 1 IL.Qk/D
u^2
2. 3 u/ 1 0 k; 3 0.6 IL
Q^0 k
D
u^2
2
.3u/ 0.432
2 0.8 0.296 4 0.4 0.208
k,3 0.6 0.568 5 0.2 0.056
6 0 0LoadP D 1 in the left span Shear force at sectionkdepends on the location of
the loadPD 1 with respect to sectionk(to the left or to the right). Calculation of
shear at sectionkis presented in Table10.5.
LoadPD 1 is in the right span In this case the shear at section k does not arise,
and influence line has zeros ordinates. The final influence line for shearQkis con-
structed using the expression (10.23). This influence line is presented in Fig.10.13c.
The same result had been obtained early by the force method.Final
Inf. line Qka3 EIIL(Z
IL (Qk) = − l 2 1 )+ IL(Qk^0 )
+ Inf. line Qk 0
−0.296 0.5680.4320.2080.056−^3 EI⋅IL(Z 1 )
− l 2+0.0480.0840.0960.0720.0720.0960.0840.0480.5160.248 0.4840.3040.128+ 0.0720.0960.084
−0.04811P = 1
13452689107kcbFig. 10.13 (a–c) Construction of influence line for shearQkDiscussion1.Influence lines forMk^0 andQk^0 for the force method are bounded by thestraight
lines, because the primary system is a set of staticallydeterminatesimply sup-
ported beams. The same influence lines in the displacement method are bounded
by thecurvedlines, because the primary system is a set of staticallyindetermi-
natebeams.