Modern Control Engineering

(Chris Devlin) #1
144 Chapter 4 / Mathematical Modeling of Fluid Systems and Thermal Systems

A–4–5. Draw a block diagram of the pneumatic controller shown in Figure 4–30. Then derive the transfer
function of this controller. Assume that Assume also that the two bellows are identical.
If the resistance Rdis removed (replaced by the line-sized tubing), what control action do we get?
If the resistance Riis removed (replaced by the line-sized tubing), what control action do we get?
Solution.Let us assume that when e=0the nozzle–flapper distance is equal to and the con-
trol pressure is equal to In the present analysis, we shall assume small deviations from the
respective reference values as follows:
small error signal
small change in the nozzle–flapper distance
small change in the control pressure
small pressure change in bellows I due to small change in the control pressure
small pressure change in bellows II due to small change in the control pressure
small displacement at the lower end of the flapper
In this controller, is transmitted to bellows I through the resistance Rd. Similarly, is trans-
mitted to bellows II through the series of resistances RdandRi. The relationship between and is

where derivative time. Similarly,pIIandpIare related by the transfer function

where integral time. The force-balance equation for the two bellows is

whereksis the stiffness of the two connected bellows and Ais the cross-sectional area of the
bellows. The relationship among the variables e, x, and yis

The relationship between and xis
pc=Kx (K>0)

pc

x=

b
a+b

e-

a
a+b

y

ApI-pIIBA=ks y

Ti=RiC=

PII(s)
PI(s)

=

1

Ri Cs+ 1

=

1

Ti s+ 1

Td=RdC=

PI(s)
Pc(s)

=

1

Rd Cs+ 1

=

1

Td s+ 1

pI pc

pc pc

y=

pII=

pI=

pc=

x=

e =

P


c^.

X


RdRi.

e

a

b

CC

X+x
Pc+pI
Pc+pII

Ps

III

Ri
Rd

Pc+pc

y

Figure 4–30
Schematic diagram
of a pneumatic
controller.

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