Example Problems and Solutions 829
Show that
where the bk’s (k=0, 1, 2,p,n)are those coefficients appearing in the numerator of the transfer
function when C(sI-A)–1B+Dis written as follows:
whereD=b 0.
Solution.Let us consider the case where n=3.We shall show that
(10–153)
Note that, by referring to Problem A–10–7, we have
Hence, we need to show that
or
WC (10–154)
0
0
- a 3
1
0
- a 2
0
1
- a 1
S =C
0
1
0
0
0
1
- a 3
- a 2
- a 1
SW
WC
0
0
- a 3
1
0
- a 2
0
1
- a 1
S W-^1 = C
0
1
0
0
0
1
- a 3
- a 2
- a 1
S
(WN) A(WN)-^1 =WCN A(N)-^1 D W-^1 =WC
0
0
- a 3
1
0
- a 2
0
1
- a 1
S W-^1
Q-^1 AQ=(WN) A(WN)-^1 = C
0
1
0
0
0
1
- a 3
- a 2
- a 1
S
C(s I-A)-^1 B+D=b 0 sn+b 1 sn-^1 +p+bn- 1 s+bn
sn+a 1 sn-^1 +p+an- 1 s+anQ-^1 B= F
bn-an b 0
bn- 1 - an- 1 b 0
b 1 - a 1 b 0V
CQ=[ 0 0 p 0 1 ]
Q-^1 AQ= G
0 1 0 0
0 0 1 0
p
p
pp0 0 0 1
- an
- an- 1
- an- 2
- a 1
W