16 · ACID–BASE EQUILIBRIA
Sulfuric acid – a diprotic acid
Sulfuric acid possesses two acidic hydrogens and is said to be diprotic. There are two
ionization steps, with sulfuric acid itself being the acid in the first step, and the
hydrogensulfate ion being the acid in the second step:
First ionization
H 2 SO 4 (aq)H 2 O(l)\===\H 3 O(aq)HSO 4 (aq) Ka(298 K) large
hydrogensulfate
ion
Second ionization
HSO 4 (aq)H 2 O(l)\===\H 3 O(aq)SO 42 (aq) Ka(298 K) 0.012 mol dm^3
The net reaction is the sum of both steps:
H 2 SO 4 (l)2H 2 O(l)\===\2H 3 O(aq)SO 42 (aq)
TheKavalues show that sulfuric acid is a strong acid and that the hydrogensulfate ion
is a relatively weak acid (although much stronger than most of the acids listed in
Table 16.2).
Dilute sulfuric acid of concentration 0.0100 mol dm^3 contains an H 3 O(aq)
concentration of 0.0145 mol dm^3 , giving a pH of 1.84. Of the total [H 3 O(aq)],
0.0100 mol dm^3 is contributed by the first ionization, and only 0.0045 mol dm^3
of the total [H 3 O(aq)] is provided by the second ionization. If both Kavalues
were large, each reaction would contribute a hydronium ion concentration of
0.0100 mol dm^3 , and the pH of the dilute acid would then be log[0.0200]1.70.
The HSO 4 ion is more than strong enough to be used as an acid in its own right,
and sodium hydrogensulfate crystals (Na,HSO 4 ) are used as a powerful disinfec-
tant. They are also provided in chemistry sets as a safe substitute for sulfuric acid.
Strong and weak bases
The commonest strong bases are the water-soluble hydroxides of sodium, potassium,
calcium, barium and lithium. These are all ionic solids. Since they are strong bases
they are completely ionized in water. For example, NaOH(s) breaks up completely in
water producing Na(aq) and OH(aq):
H 2 O
Na,OH(s) —Na(aq)OH(aq)
sodium hydroxide hydroxide ion
For example, a solution containing 0.5 mol of dissolved NaOH per dm^3 of solution
contains 0.5 mol dm^3 of OH(aq).
A second category of bases are those which produce hydroxide ions in solution by
reactionwith water. An example is ammonia:
NH 3 (aq)H 2 O(l)\===\NH 4 (aq) OH(aq)
Ammonia is a weak basebecause it is incompletely ionized in solution, and
Kb(T)
[NH 4 (aq)][OH(aq)]
[NH 3 (g)]
whereKb(T)is the basicity constant(ordissociation constant) of ammonia at
temperatureT. Generalizing, the basicity constant for a base B is the equilibrium
constant for the reaction:
B(aq)H 2 O(l)\===\BH(aq)OH(aq) (16.8)
294