INFRARED SPECTROSCOPY
20.23). The –OH bond in carboxylic acids, also very broad, is found between 3500
and 2400 cm–1(see ethanoic acid Fig. 20.20). The spectra of carboxylic acids is
easily distinguished from that of alcohols and phenols, since acid spectra also con-
tain the characteristic C=O peak.
●The NH 2 group gives rise to two weak absorptions (due to the N–H stretch) in the
range 3500–3100 cm–1(see propan-2-amine, Fig. 20.24).
●Nitriles (also known as cyanides), show a CN stretch near 2250 cm–1(see etha-
nenitrile, Fig. 20.25).
The spectra in Figs 20.17–20.25 show the potential of infrared spectroscopy for dis-
tinguishing between common types of organic molecule, particularly if combined
with information from other techniques such as mass spectrometry, nuclear mag-
netic resonance (NMR) and with the results of chemical tests.
385
Example 20.3
A compound P contains the following elements (percentage by
mass):
C (30.6%), H (3.80%), O (20.3%), Cl (45.2%)
Its mass spectrum contains a parent ion at m/e= 78. Its infrared
spectrum contains a very strong peak at 1800 cm–1. P does not
reduce Fehling’s solution. Suggest a molecular formula for P.
Answer
The simplest formula of the compound is first calculated from the percentage of
elements by mass:
Element Carbon Hydrogen Oxygen Chlorine
Percentage by mass 30.6% 3.80% 20.3% 45.2%
Molar ratio 30.6 3.80 20.3 45.2
——– = 2.55 ——– = 3.80 ——– = 1.27 ——– = 1.27
12.0 1.0 16.0 35.5
Simplest molar ratio 2.55 3.80 1.27 1.27
——– = 2.00 ——– = 3.00 ——– = 1.00 ——– = 1.00
1.27 1.27 1.27 1.27
Simplest whole number ratio 2311
Therefore, the simplest formula of the substance is C 2 H 3 OCl. The mass spectrum
gives the mass of the parent ion as 78 u (^35 Cl isotope), and we conclude that the
molecule has the formula C 2 H 3 OCl.
The peak at 1800 cm–1suggests the presence of a carbonyl group. Taking
‘C=O’ out of the formula C 2 H 3 OCl gives CH 3 Cl. P does not reduce Fehling’s
solution, which excludes the aldehyde CH 2 ClCHO. The structure for P is then most
likely to be CH 3 COCl:
HO
| ⁄⁄
H⎯C⎯C
| \
HCl
Using IR spectra in
organic analysis 1
Which of the following
compounds would be
expected to show (i)a peak
due to C=O, (ii)a broad
band due to –OH, (iii)a
peak due to C–H?
(a)butanol
(b)propanoic acid
(c)ethanal.
Exercise 20J
Using IR spectra in
organic analysis 2
A compound Y contains (by
mass) 19.2% nitrogen,
15.1% hydrogen and 65.8%
carbon. Its mass spectrum
contained an intense peak,
due to the parent ion, at
m/e= 73. Its infrared spec-
trum contained two peaks
of medium intensity at
3300 cm–1and 3370cm–1.
Suggest a formula for Y.
Exercise 20K