The differential flux dfenclosed in a ring of thickness
dy, from pointD 1 to pointD 2 , for a 1-m length of
conductor isdf¼Bydy¼
m 0
2 pI
ydyðÞWb=m (13:20)As the total currentIflows in the surface conductor,
then the differential flux linkage dlhas the same
magnitude as the differential flux df.dl¼df¼m 0
2 pI
y
dyðÞWb=m (13:21)The total external flux linkage enclosed by the ring is
obtained by integrating fromD 1 toD 2l 1 2 ¼ðD 2D 1dl¼m 0
2 p
IðD 2D 1dy
y
¼m 0
2 p
IlnD 1
D 2
ðÞWb=m (13:22)In general, the total external flux linkage from the surface of the conductor to any pointD, per unit
length, is
lext¼ðDrdl¼
m 0
2 pIln
D
r
ðÞWb=m (13:23)The summation of the internal and external flux linkage at any pointDpermits evaluation of the total
inductance of the conductorLtot, per unit length, as follows:
lintlþlext¼
m 0
2 pI
1
4þln
D
r
¼
m 0
2 pI ln
D
e^1 =^4 r
ðÞWb=m (13:24)Ltot¼
lintþlext
I¼
m 0
2 pln
D
GMR
ðÞH=m (13:25)where GMR (geometric mean radius)¼e^1 =^4 r¼0.7788r
GMR can be considered as the radius of a fictitious conductor assumed to have no internal flux but
with the same inductance as the actual conductor with radiusr.
13.4.4 Inductance of a Two-Wire Single-Phase Line
Now, consider a two-wire single-phase line with solid cylindrical conductors A and B with the same
radiusr, same lengthl, and separated by a distanceD, whereD>r, and conducting the same currentI,as
shown in Fig. 13.9. The current flows from the source to the load in conductor A and returns in
conductor B (IA¼IB).
The magnetic flux generated by one conductor links the other conductor. The total flux linking
conductor A, for instance, has two components: (a) the flux generated by conductor A and (b) the flux
generated by conductor B which links conductor A.
As shown in Fig. 13.10, the total flux linkage from conductors A and B at pointPis
lAP¼lAAPþlABP (13:26)lBP¼lBBPþlBAP (13:27)Irdyy
D 1 D 2
xFIGURE 13.8 External magnetic field.