H = Ks COS^2 Ct + C cos a (11)
V=y 2 Kssm2a + Csma (12)
Elevation of N= elevation of O + OM + V-NQ (13)
where K = stadia interval factor; C = distance from center of instrument to principal
focus.
- Substitute numerical values in the above equations
The results obtained are shown:
Point H, ft(m) ^,ft(m) Elevation, ft (m)
1 544.8(166.06) 25.4 (7.74) 505.6(154.11)
2 622.0(189.59) 34.8 (10.61) 520.0(158.50)
3 482.5(147.07) -15.7 (-4.79) 468.5(142.80)
VOLUME OF EARTHWORK
Figure 10« and b represent two highway cross sections 100 ft (30.5 m) apart. Compute the
volume of earthwork to be excavated, in cubic yards (cubic meters). Apply both the aver-
age-end-area method and the prismoidal method.
Calculation Procedure:
- Resolve each section into an isosceles trapezoid and a triangle;
record the relevant dimensions
Let A 1 and A 2 denote the areas of the end sections, L the intervening distance, and V the
volume of earthwork to be excavated or filled.
Method 1: The average-end-area method equates the average area to the mean of the
two end areas. Then
L(A 1 ^-A 2 )
V= \ (14)
Figure 1Oc shows the first section resolved into an isosceles trapezoid and a triangle,
along with the relevant dimensions.
- Compute the end areas, and apply Eq. 14
Thus: A 1 = [24(40 + 64) + (32 - 24)64]/2 = 1504 ft
2
(139.72 m
2
); A 2 = [36(40 + 76) + (40
- 36)76]/2 - 2240 ft
2
(208.10 m
2
); V= 100(1504 + 2240)/[2(27)] = 6933 yd
3
(5301.0 m
3
).
- Apply the prismoidal method
Method 2: The prismoidal method postulates that the earthwork between the stations is a
prismoid (a polyhedron having its vertices in two parallel planes). The volume of a pris-
moid is
y=_±_lL(A «^1 + 4Am 27 + A^2 ) (15)
6