(a) Elevation normal to line of flight (c) Elevation parallel
to line of flight
FIGURE 32
XA = (XJp)B and YA = (yalp)B. Then XR = (+86.46/92.03)5 = +0.93955; YR =
(-54.32/92.03)5 = -0.59025; X 8 = (+29.41/91.85)5 = +0.32025; Y 8 = (+56.93/91.85)5 =
+0.61985.
- Express the distance between the control points in terms of the
air base; solve the resulting equation
Disregarding the difference in elevation of the two points, we have (RS)
2
= (XR-XS)
2- (YR- Y 8 )
2
. Now,XR-XS = +0.61935 and YR- Y 8 = -1.21005. Then 2073
2
= [(0.6193)
2- (1.2100)^2 ]5^2 ,or5=1525m.
- (YR- Y 8 )
Datum plane
Plane of
photograph
B = Air base
(b) Plan
Photograph I Photograph 2
Direction of
flight