Handbook of Civil Engineering Calculations

(singke) #1
Then^m = 2051/212.5 = 9.7 in (246 A mm). Since the area is symmetric with respect to
the y axis, this is also a centroidal axis. The intersection point G of the ;c and y axes is,
therefore, the centroid of the area.


  1. Compute the distance between the centroidal axis and the
    reference axis
    Compute k, the distance between the horizontal centroidal axis of each element and the x
    axis. Only absolute values are required. Thus Ar 1 = 9.7 - 4.0 = 5.7 in (1448 mm); k 2 = 9.7 -
    8.0 = 1.7 in (43.2 mm); k 3 = 13.4 - 9.7 = 3.7 in (94.0 mm).

  2. Compute the moment of inertia of the entire area—x axis
    Let /o denote the moment of inertia of an element with respect to its horizontal centroidal
    axis and A its area. Compute the moment of inertia Ix of the entire area with respect to the
    jc axis by applying the transfer equation Ix 2/ 0 + ^AK^2. Thus


Element /o, in^4 (dm^4 ) Ak^2 , in^4 (dm^4 )
1 1 /36(16)(6)^3 = 96(0.40) 48(5.7)^2 =1560(6.49)
2 yi2(16)(4)^3 = 85(0.35) 64(1.7)^2 = 185 (0.77)
3 0.110(8)^4 = 451 (1.88) 100.5(3.7)^2 = 1376 (5.73)
Total 632(2.63) 3121(12.99)

Then, Ix = 632 + 3121 = 3753 in^4 (15.62 dm^4 ).


  1. Determine the moment of inertia of the entire area—y axis
    For this computation, subdivide element 1 into two triangles having the y axis as a base.
    Thus


Element / about y axis, in^4 (dm^4 )
1 2e/, 2 )(6)(8)^3 = 512 (2.13)
2 yi2(4)(16)^3 = 1365 (5.68)
3 /2(0.785XS)^4 = 1607 (6.89)
/,= 3484(14.5)


  1. Compute the polar moment of inertia of the area
    Apply the equation for the polar moment of inertia J 0 with respect to G: JG = Ix + Iy =
    3753 + 3484 = 7237 in^4 (30.12 dm^4 ).

  2. Determine the moment of inertia of the entire area—w axis
    Apply the equation in step 5 to determine the moment of inertia Iw of the entire area with
    respect to the horizontal axis w through A. Thus k= 15.0 - 9.7 = 5.3 in (134.6 mm); Iw =
    1, + AJc^1 = 3753 + 212.5(5.3)^2 = 9722 in^4 (40.46 dm^4 ).

  3. Compute the polar moment of inertia
    Compute the polar moment of inertia of the entire area with respect to A. Then JA=Iw + Iy
    = 9722 ± 3484 = 13,206 in^4 (54.97 dm^4 ).

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