Calculation Procedure:
- Determine the relationship
between the torque in the shaft
segments
Since segments AB and BC (Fig. 24) are
twisted through the same angle, the torque
applied at the junction of these segments is
distributed in proportion to their relative
rigidities. Using the subscripts s and b to ™T>,TTT»T. ** ^ j i ^
denote steel and bronze, respectively, we FIGURE^24 ' ComP°und shafi
see that O = T 5 LJ(JsG 5 ) = W(J,G,),
where the symbols are as given in the pre-
vious calculation procedure. Solving
yields Ts = (5/4.5)(34/44)( 12/6)7; = 0.703
Tb.- Establish the relationship between the shearing stresses
For steel, sss = 16T 5 I(TiD^3 ), where the symbols are as given earlier. Thus S 55 =
16(0.703F 6 )/(Tr3^3 ). Likewise, for bronze, ssb = 167y(Tr4^3 ), /. sss = 0.703(4^3 /3^3 > 5 =
1.67rf. - Compute the allowable torque
Ascertain which material limits the capacity of the member, and compute the allowable
torque by solving the shearing-stress equation for T.
If the bronze were stressed to 10,000 lb/in^2 (69.0 MPa), inspection of the above rela-
tions shows that the steel would be stressed to 16,700 lb/in^2 (115.1 MPa), which exceeds
the allowed 15,000 lb/in^2 (103.4 MPa). Hence, the steel limits the capacity. Substituting
the allowed shearing stress of 15,000 lb/in^2 (103.4 MPa) gives T 5 = 15,000ir(3^3 )/[16(12) =
6630 lb-ft (8984.0 N-m); also, Tb = 6630/0.703 = 9430 lb-ft (12,777.6 N-m). Then T =
6630 + 9430 = 16,060 lb-ft (21,761.3 N-m).
Stresses in Flexural MembersIn the analysis of beam action, the general assumption is that the beam is in a horizontal
position and carries vertical loads lying in an axis of symmetry of the transverse section
of the beam.
The vertical shear V at a given section of the beam is the algebraic sum of all vertical
forces to the left of the section, with an upward force being considered positive.
The bending moment M at a given section of the beam is the algebraic sum of the
moments of all forces to the left of the section with respect to that section, a clockwise
moment being considered positive.
If the proportional limit of the beam material is not exceeded, the bending stress (also
called the flexural, or fiber, stress) at a section varies linearly across the depth of the sec-
tion, being zero at the neutral axis. A positive bending moment induces compressive
stresses in the fibers above the neutral axis and tensile stresses in the fibers below. Conse-
quently, the elastic curve of the beam is concave upward where the bending moment is
positive.
Bronze Steel