Diagram A Full load on entire span
Diagram B Dead load on overhangs; full load
between supports
(b) Bending-moment diagrams
FIGURE 27
Calculation Procedure:
- Place full load on the overhangs, and compute the
negative moment
Refer to the moment diagrams. For every position of the supports, there is a correspon-
ding maximum bending stress. The position for which this stress has the smallest value
must be identified.
As the supports are moved toward the interior of the beam, the bending moments be-
tween the supports diminish in algebraic value. The optimal position of the supports is
that for which the maximum potential negative moment M 1 is numerically equal to the
maximum potential positive moment M 2. Thus, M 1 = -1.2w(x^2 /2) = — 0.6w;t^2. - Place only the dead load on the overhangs and the full load
between the supports. Compute the positive moment.
Sum the areas under the shear diagram to compute M 2. Thus, M 2 =^1 A[1.2w(L/2 - x)^2 -
0.2w.r^2 ] = w(0.15L^2 - 0.6Lx + 0.5*^2 ). - Equate the absolute values of M 1 and M 2 and solve for x
Substituting gives 0.6^2 = 0.15L^2 - 0.6Lx + 0.5^2 ; x = 110.5°^5 - 3) = 0.240L.
FLEXURAL CAPACITY OFA COMPOUND BEAM
A Wl6 x 45 steel beam in an existing structure was reinforced by welding an WT6 x 20
to the bottom flange, as in Fig. 28. If the allowable bending stress is 20,000 lb/in^2
(137,900 kPa), determine the flexural capacity of the built-up member.
(a) Loads carried by overhanging beam