Concise Physical Chemistry

(Tina Meador) #1

c05 JWBS043-Rogers September 13, 2010 11:25 Printer Name: Yet to Come


76 ENTROPY AND THE SECOND LAW

We know from the second law that at constant pressure, we obtain

dS=

dqp
T

=


Cp
T
so

dS=

Cp
T

dT+

(


∂S


∂p

)


T

dp

By the Euler reciprocity relation, for exact differentialsduwritten in differential form

du=M(x,y)+N(x,y)

we have the equality

∂M(x,y)
dy

=


N(x,y)
dx

In the case of the Gibbs thermodynamic function (next chapter)μ=f(S,p), we
have

dμ=−SdT+Vdp

so


(


∂S


∂p

)


T

=


(


∂V


∂T


)


p

which leads to

dS=

Cp
T

dT+

(


∂S


∂p

)


T

dp=

Cp
T

dT−

(


∂V


∂T


)


p

dp

Both of these coefficientsCp/Tand(∂V/∂T)pcan be measured, so the infinitesimal
dScan be found at anyTandV. The finite changeSis

S=


∫T 2


T 1

Cp
T

dT−

∫p 2

p 1

(


∂V


∂T


)


p

dp

Starting with the Helmholtz free energy in place of the Gibs function, a comparable
derivation yields

S=


∫T 2


T 1

Cp
T

dT−

∫V 2


V 1

(


∂p
∂T

)


V

dV
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