c05 JWBS043-Rogers September 13, 2010 11:25 Printer Name: Yet to Come
76 ENTROPY AND THE SECOND LAW
We know from the second law that at constant pressure, we obtain
dS=
dqp
T
=
Cp
T
so
dS=
Cp
T
dT+
(
∂S
∂p
)
T
dp
By the Euler reciprocity relation, for exact differentialsduwritten in differential form
du=M(x,y)+N(x,y)
we have the equality
∂M(x,y)
dy
=
N(x,y)
dx
In the case of the Gibbs thermodynamic function (next chapter)μ=f(S,p), we
have
dμ=−SdT+Vdp
so
−
(
∂S
∂p
)
T
=
(
∂V
∂T
)
p
which leads to
dS=
Cp
T
dT+
(
∂S
∂p
)
T
dp=
Cp
T
dT−
(
∂V
∂T
)
p
dp
Both of these coefficientsCp/Tand(∂V/∂T)pcan be measured, so the infinitesimal
dScan be found at anyTandV. The finite changeSis
S=
∫T 2
T 1
Cp
T
dT−
∫p 2
p 1
(
∂V
∂T
)
p
dp
Starting with the Helmholtz free energy in place of the Gibs function, a comparable
derivation yields
S=
∫T 2
T 1
Cp
T
dT−
∫V 2
V 1
(
∂p
∂T
)
V
dV