c07 JWBS043-Rogers September 13, 2010 11:25 Printer Name: Yet to Come
94 EQUILIBRIUM
and
GB=G◦B+RTln
pB
1. 0
where the 1.0 in the denominators signify that the partial pressures are relative to
the standard state of 1.0 bar. The difference between the chemical potentials of the
reactant state and product state is
rG=
∑
G(prod)−
∑
G(react)
which in this simple case is
rG=GB−GA=G◦B−G◦A+RTln
pB
1. 0
−RTln
pA
1. 0
or
rG=G◦+RTln
pB
pA
As the reaction progresses,rGis not zero andGof the reacting system is not constant
with timet,(∂G/∂t)T,p=0. When the chemical reaction has come to completion,
the pressure quotientQ=pB/pAhas arrived at a value such that(∂G/∂t)T,p=0,
hence
rG=G◦+RTln
pB
pA
= 0
The free energy change of the system has arrived at a Gibbs potential energy mini-
mum. Under these andonly under these conditions,wehaverG=0, so that
G◦=−RTln
pB
pA
=−RTlnKeq
The expression is frequently written in the equivalent form:
Keq=e−G
◦/RT
7.2 GENERAL FORMULATION
A more general formulation of the equilibrium expressions above is given by the
reaction
aA+bB+... = cC+dD+...