Microsoft Word - Digital Logic Design v_4_6a

 Solution

• R= Vg/Ig = 1000/0.005 = 200 kΩ
  Pr = Ig^2 R = (.005)^2 (200,000)= 5 W

Circuit simplification by combining resistors
 Resistors in Series
Resistors in series can be replaced by an equivalent resistor that is the sum of all the
resistors in series.

 Resistors in Parallel

Resistors in parallel can be replaced by an equivalent resistor as shown below:

Example
Find values of I 1 and I 2 for the following circuit:

Solution:

1) Simplify the circuit by combining the two 1 M Ω parallel resistors with the 1 kΩ resistor that is in

1 kΩ (^) 1 M Ω

+

+5V

-

I 1 I 2

1 kΩ

1 M Ω

R 1 R 2... Rn^ 1/Req = 1/R 1 + 1/R 2 + ... + 1/R n

R 1 R 2 Rn

...

Req = R 1 + R 2 + ...+ R n

+

-

Vg (^) R
Ig