Microsoft Word - Digital Logic Design v_4_6a

series with them.

2) Redraw the circuit and apply Ohms law (V=I*R) to find currents.

I 1 = V / R = 5 / 1000 = 0.005 A = 5 mA

I 2 = V / R = 5 / 501000 = 0.00001 A = 10 uA

Note: The amount of current through each resistor is inversely proportional to the size of the

resistors.

Using a switch to create logic 1 “+5 v” and logic 0 “Ground or 0 v”

1 k Ω

Switch

+

+5V

-

Output:

”1” when switch is open

”0” when switch is closed

Typically

drawn as

1 k Ω

Vcc

Gnd

Output

1 kΩ

+

+5V

-

I (^1) I 2
501 k Ω
1 kΩ (^) 1 M Ω

+

+5V

-

I 1 I 2

1 kΩ

1 M Ω

1/R 1 = 1/10^6 + 1/10^6 = 2/10^6 R 1 = 500 kΩ

R 2 = 500 + 1 = 501 kΩ