http://www.ck12.org Chapter 10. The Mole
A compound of iron and oxygen is analyzed and found to contain 69.94% iron and 30.06% oxygen by mass. Find
the empirical formula of the compound.
Answer:
Follow the steps outlined in the text.
- Assume a 100 g sample. In 100 grams of the compound, there would be 69.94 g Fe and 30.06 g O.
- Convert to moles.
69 .94 g Fe×
1 mol Fe
55 .85 g Fe
= 1 .252 mol Fe
30 .06 g O×
1 mol O
16 .00 g O
= 1 .879 mol O
- Divide both values by the smallest of the results.
1 .252 mol Fe
1. 252
=1 mol Fe
1 .879 mol O
1. 252
= 1 .501 mol O
- Since the moles of O is still not a whole number, both numbers can be multiplied by 2. The results are now close
enough to be rounded to the nearest whole number.
1 mol Fe× 2 =2 mol Fe
1 .501 mol O× 2 =3 mol O
The empirical formula of the compound is Fe 2 O 3.
Molecular Formulas
Molecular formulastell us how many atoms of each element are present in one molecule of a molecular compound.
In many cases, the molecular formula is the same as the empirical formula. For example, the molecular formula of
methane is CH 4 , and because 1:4 is the smallest whole-number ratio that can be written for this compound, that is
also its empirical formula. Sometimes, however, the molecular formula is a simple whole-number multiple of the
empirical formula. Acetic acid is an organic acid that gives vinegar its distinctive taste and smell. Its molecular
formula is C 2 H 4 O 2. Glucose is a simple sugar that cells use as their primary source of energy. Its molecular formula
is C 6 H 12 O 6. The structures of both molecules are shown inFigure10.6. They are very different compounds, yet
both have the same empirical formula, CH 2 O.
The followingTable10.1 shows a few other compounds with their empirical and molecular formulas:
TABLE10.1:Empirical and Molecular Formulas
Compound Empirical Formula Molecular Formula
water H 2 O H 2 O
hydrogen peroxide HO H 2 O 2
methane CH 4 CH 4
butane C 2 H 5 C 4 H 10 239