http://www.ck12.org Chapter 14. The Properties of Gases
T 1 = 25 ◦C+ 273 =298 K
T 2 = 50 ◦C+ 273 =323 K
V 1 =752 mL
V 2 =?
V 1
T 1
=
V 2
T 2
V 2 =
V 1 T 2
T 1
V 2 =
(752 mL)(323 K)
298 K
V 2 =815 mL
Gay-Lussac’s Law
Gay-Lussac’s Lawdescribes the relationship between pressure and absolute temperature:
P
T=k
P 1
T 1 =
P 2
T 2
Gay-Lussac’s law says that at a constant volume, the pressure of a gas is directly proportional to its absolute
temperature. This relationship is also sometimes attributed to Guillaume Amontons (1663–1705). Although his
work predated that of Gay-Lussac by over a century, the data on which he based his ideas were considerably less
precise, due to the cruder instrumentation available at the time.
Example 14.5
The gas in an aerosol can exerts a pressure of 3.00 atm at 25°C. Directions on the can warn the user not to keep the
can in a place where the temperature exceeds 52°C. What would the gas pressure in the can be at 52°C? Before you
begin, do you think the pressure should go up, down or stay the same?
Answer:
Again, don’t forget that all temperatures must be converted to absolute temperature (Kelvin).
T 1 = 25 ◦C+ 273 =298 K
T 2 = 52 ◦C+ 273 =325 K
P 1 = 3 .00 atm
P 2 =?
P 1
T 1
=
P 2
T 2
P 2 =
P 1 T 2
T 1
P 2 =
( 3 .00 atm)(325 K)
298 K
P 2 = 3 .27 atm
Note that the pressure increases, which would be expected if the temperature were to go up.