222 SOLUTIONS
harmonicoscillator offrequency whoseenergylevels are
The average energy in the circuit is given by (with
The average energy is equally distributedbetween the capacitance and the
inductance:
where V is the voltage across the capacitor (between points A and B; see
FigureS.4.96). We then have
In the classical limit
We could equally well have derived the classical result by using the equipar-
tition theorem (see Problem4.42). For the single degree of freedom, there
is an average energy which, as noted, is divided between the capacitor
and inductor, so
a)
where is the charge on the capacitor. This is theHamiltonian of a