The only change from the harmonic oscillator for a single spring is that,
with two identical springs, the effective spring constant is 2 K.
b) The eigenfunction of the ground state is
c) When one spring is cut, the particle is now coupled to only a single
spring. So we must replace 2K in the above equations by K. The ground
state eigenfunction is now
Notice that The amplitude I for remaining in the ground state
is found, in the sudden approximation, by taking the overlap integral of the
two ground state wave functions. The probability of remaining in the
ground state is the square of this overlap integral:
where we have used in deriving the last line. The probability
of remaining in the ground state is close to unity.
Angular Momentum and Spin
5.22 Given Another Eigenfunction (Stony Brook)
a) The factor cos indicates that it is a state which has an angular
momentum of 1.
266 SOLUTIONS