576 10 Particle Physics – II
Fig. 10.9
Actually the value of Rwill be slightly greater than 2 because of an
increased value ofαs, the running coupling constant.
10.58 E=〈ψ|H|ψ〉
/
〈ψ|ψ〉=
∫∞
0
e−r/a
{
−
^2
2 μ
[
d^2
dr^2
+
2
r
d
dr
]
+Br
}
e−r/a. 4 πr^2 dr
∞∫
0
e−^2 r/a. 4 πr^2 dr
whereμ=mq
/
2 is the reduced mass
E=
^2
2 μ
1
a^2
+
3
2
Ba (1)