114 CHAPTER 4 CONTINUOUS RANDOM VARIABLES AND PROBABILITY DISTRIBUTIONS
Figure 4-15 Standardizing a normal random variable.
4 7 9 10 13 16 x
–3 –1.5 – 0.5 0 1.5 3 z
11
0.5
0 1.5
Distribution of Z =X σ–μ
Distribution of X
10 13 x
z
Suppose Xis a normal random variable with mean and variance 2. Then,
(4-11)
where Zis a standard normal random variable,and is thez-value
obtained by standardizingX.
The probability is obtained by entering Appendix Table II with z 1 x 2 .
z
1 x 2
P 1 Xx 2 P a
X
x
bP^1 Zz^2
EXAMPLE 4-14 Continuing the previous example, what is the probability that a current measurement is be-
tween 9 and 11 milliamperes? From Fig. 4-15, or by proceeding algebraically, we have
Determine the value for which the probability that a current measurement is below
this value is 0.98. The requested value is shown graphically in Fig. 4-16. We need the value of
xsuch that P(Xx) 0.98. By standardizing, this probability expression can be written as
Appendix Table II is used to find the z-value such that P(Z z) 0.98. The nearest proba-
bility from Table II results in
P 1 Z2.05 2 0.97982
0.98
P 1 Z 1 x 102 22
P 1 Xx 2 P 11 X 102 2 1 x 102 22
0.691460.308540.38292
P 1 0.5Z0.5 2 P 1 Z0.5 2 P 1 Z0.5 2
P 19 X 112 P 119 102 2 1 X 102 2 111 102 22
In the preceding example, the value 13 is transformed to 1.5 by standardizing, and 1.5 is
often referred to as the z-valueassociated with a probability. The following summarizes the
calculation of probabilities derived from normal random variables.
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