116 CHAPTER 4 CONTINUOUS RANDOM VARIABLES AND PROBABILITY DISTRIBUTIONS
Therefore,
and
Suppose a digital 1 is represented as a shift in the mean of the noise distribution to 1.8
volts. What is the probability that a digital 1 is not detected? Let the random variable Sdenote
the voltage when a digital 1 is transmitted. Then,
This probability can be interpreted as the probability of a missed signal.
EXAMPLE 4-16 The diameter of a shaft in an optical storage drive is normally distributed with mean 0.2508
inch and standard deviation 0.0005 inch. The specifications on the shaft are 0.2500 0.0015
inch. What proportion of shafts conforms to specifications?
Let Xdenote the shaft diameter in inches. The requested probability is shown in Fig. 4-18 and
Most of the nonconforming shafts are too large, because the process mean is located very near
to the upper specification limit. If the process is centered so that the process mean is equal to
the target value of 0.2500,
By recentering the process, the yield is increased to approximately 99.73%.
0.9973
0.998650.00135
P 1 Z 32 P 1 Z 32
P 1 3 Z 32
P 1 0.2485X0.2515 2 P a
0.24850.2500
0.0005
Z
0.25150.2500
0.0005
b
0.919240.00000.91924
P 1 4.6Z1.4 2 P 1 Z1.4 2 P 1 Z4.6 2
P 1 0.2485X0.2515 2 P a
0.24850.2508
0.0005
Z
0.25150.2508
0.0005
b
P 1 S0.9 2 P a
S1.8
0.45
0.91.8
0.45
bP 1 Z 22 0.02275
x2.58 1 0.45 2 1.16
x 0.452.58
0.2515
f(x)
0.2508
0.25
0.2485 x
Specifications
Figure 4-18
Distribution for
Example 4-16.
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