168 CHAPTER 5 JOINT PROBABILITY DISTRIBUTIONS
The requested probability is P(X 1
1000,X 2
1000,X 3
1000,X 4
1000), which
equals the multiple integral of over the region x 1
1000, x 2
1000,
x 3
1000,x 4
1000. The joint probability density function can be written as a product of
exponential functions, and each integral is the simple integral of an exponential function.
Therefore,
Suppose that the joint probability density function of several continuous random vari-
ables is a constant, say cover a region R(and zero elsewhere). In this special case,
by property (2) of Equation 5-22. Therefore, (R). Furthermore, by property (3)
of Equation 5-22.
When the joint probability density function is constant, the probability that the random vari-
ables assume a value in the region Bis just the ratio of the volume of the region to the
volume of the region Rfor which the probability is positive.
EXAMPLE 5-24 Suppose the joint probability density function of the continuous random variables Xand Yis
constant over the region Determine the probability that
The region that receives positive probability is a circle of radius 2. Therefore, the area of
this region is 4. The area of the region is . Consequently, the requested prob-
ability is 14 2 1 4.
x^2 y^21
x^2 y^2 4. X^2 Y^2 1.
B ̈R
volume 1 B ̈R 2
volume 1 R 2
B
pfX 1 X 2 p Xp 1 x 1 , x 2 ,p, xp 2 dx 1 dx 2 pdxpc volume 1 B ̈R 2
P 31 X 1 , X 2 ,p, Xp 2 B 4
c 1 volume
(^)
p
fX 1 X 2 p Xp 1 x 1 , x 2 ,p, xp 2 dx 1 dx 2 pdxpc 1 volume of region R 2 1
P 1 X 1
1000, X 2
1000, X 3
1000, X 4
10002 e^1 ^2 1.5^3 0.00055
fX 1 X 2 X 3 X 4 1 x 1 , x 2 , x 3 , x 42
If the joint probability density function of continuous random variables
is the marginal probability density functionof is
(5-23)
where denotes the set of all points in the range of for which
Xixi.
Rxi X 1 , X 2 ,p, Xp
fXi 1 xi 2
Rxi
p fX 1 X 2 pXp 1 x 1 , x 2 ,p, xp 2 dx 1 dx 2 pdxi 1 dxi 1 pdxp
fX 1 X 2 pXp 1 x 1 , x 2 p, xp 2 Xi
X 1 ,X 2 ,p, Xp
Definition
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