EXAMPLE 10-13 A company manufactures impellers for use in jet-turbine engines. One of the operations
involves grinding a particular surface finish on a titanium alloy component. Two different
grinding processes can be used, and both processes can produce parts at identical mean sur-
face roughness. The manufacturing engineer would like to select the process having the
least variability in surface roughness. A random sample of n 1 11 parts from the first
process results in a sample standard deviation s 1 5.1 microinches, and a random sample
of n 2 16 parts from the second process results in a sample standard deviation of s 2 4.7
microinches. We will find a 90% confidence interval on the ratio of the two standard devi-
ations,
Assuming that the two processes are independent and that surface roughness is normally
distributed, we can use Equation 10-31 as follows:or upon completing the implied calculations and taking square roots,Notice that we have used Equation 10-28 to find f0.95,15,10 1 f0.05,10,15 1 2.540.39.
Since this confidence interval includes unity, we cannot claim that the standard deviations of
surface roughness for the two processes are different at the 90% level of confidence.EXERCISES FOR SECTION 10-50.678 1
2 1.8871 5.1 22
1 4.7 220.39^21
^221 5.1 22
1 4.7 222.85s^21
s^22f0.95,15,10^21
^22s^21
s^22f0.05,15,10 1
2.
360 CHAPTER 10 STATISTICAL INFERENCE FOR TWO SAMPLESIf and are the sample variances of random samples of sizes n 1 and n 2 , respec-
tively, from two independent normal populations with unknown variances and
then a 100(1)% confidence interval on the ratio is(10-31)where and are the upper and lower 2 percentage
points of the Fdistribution with n 2 1 numerator and n 1 1 denominator degrees
of freedom, respectively. A confidence interval on the ratio of the standard deviations
can be obtained by taking square roots in Equation 10-31.f 2,n 2 1,n 1 1 f 1 2,n 2 1,n 1 1s^21
s^22f 1 2,n 2 1,n 1 1 ^21
^22s^21
s^22f 2,n 2 1,n 1 1^21 ^22
^21 22 ,s^21 s^22Definition10-45. For an Fdistribution, find the following:
(a)f0.25, 5, 10 (b)f0.10, 24, 9
(c)f0.05, 8, 15 (d)f0.75, 5, 10
(e)f0.90, 24, 9 (f )f0.95, 8, 15
10-46. For an Fdistribution, find the following:
(a)f0.25, 7, 15 (b)f0.10, 10, 12(c)f0.01, 20, 10 (d)f0.75, 7, 15
(e)f0.90, 10, 12 (f)f0.99, 20, 10
10-47. Two chemical companies can supply a raw material.
The concentration of a particular element in this material is
important. The mean concentration for both suppliers is the
same, but we suspect that the variability in concentration mayc 10 .qxd 5/16/02 1:31 PM Page 360 RK UL 6 RK UL 6:Desktop Folder:TEMP WORK:MONTGOMERY:REVISES UPLO D CH114 FIN L:Quark Files: