For a one-sided alternative, replace in Equation 10-38 by z.10-6.4 Confidence Interval for p 1 p 2The confidence interval for p 1 p 2 can be found directly, since we know thatis a standard normal random variable. Thus P(z 2 Zz 2 ) 1 , so we can substi-
tute for Zin this last expression and use an approach similar to the one employed previously
to find an approximate 100(1 )% two-sided confidence interval for p 1 p 2.ZPˆ 1 Pˆ 2 1 p 1 p 22Bp 111 p 12
n 1p 211 p 22
n 2z 210-6 INFERENCE ON TWO POPULATION PROPORTIONS 365For the two-sided alternative, the common sample size is(10-38)where q 1 1 p 1 and q 2 1 p 2.n3 z 211 p 1
p 221 q 1
q 22 2
z 1 p 1 q 1
p 2 q 242
1 p 1 p 222If and are the sample proportions of observation in two independent random
samples of sizes n 1 and n 2 that belong to a class of interest, an approximate two-
sided 100(1)% confidence interval on the difference in the true proportions
p 1 p 2 is(10-39)where z 2 is the upper 2 percentage point of the standard normal distribution.p 1 p 2 pˆ 1 pˆ 2
z 2
Bpˆ 111 pˆ 12
n 1pˆ 211 pˆ 22
n 2pˆ 1 pˆ 2 z 2
Bpˆ 111 pˆ 12
n 1pˆ 211 pˆ 22
n 2pˆ 1 pˆ 2DefinitionEXAMPLE 10-15 Consider the process manufacturing crankshaft bearings described in Example 8-6.
Suppose that a modification is made in the surface finishing process and that, subse-
quently, a second random sample of 85 axle shafts is obtained. The number of defective
shafts in this second sample is 8. Therefore, since n 1 85, n 2 85, andpˆ 2 (^8) 85 0.09, we can obtain an approximate 95% confidence interval on the
pˆ 1 0.12,
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