Applied Statistics and Probability for Engineers

(Chris Devlin) #1
2-3

EXAMPLE S2-4 A part is labeled by printing with four thick lines, three medium lines, and two thin lines. If
each ordering of the nine lines represents a different label, how many different labels can be
generated by using this scheme?
From Equation S2-3, the number of possible part labels is

Combinations
Another counting problem of interest is the number of subsets of relements that can be se-
lected from a set of nelements. Here, order is not important. Every subset of relements can
be indicated by listing the elements in the set and marking each element with a “*” if it is to
be included in the subset. Therefore, each permutation of r*’s and n rblanks indicate a dif-
ferent subset and the number of these are obtained from Equation S2-3.
For example, if the set is S= {a, b, c, d} the subset {a, c} can be indicated as

abcd
**

9!
4! 3! 2!

 2520

The number of subsets of size rthat can be selected from a set of nelements is
denoted as or and

a (S2-4)

n
r

b

n!
r! 1 nr 2!

1 nr 2 Cnr

EXAMPLE S2-5 A printed circuit board has eight different locations in which a component can be placed. If
five identical components are to be placed on the board, how many different designs are pos-
sible?
Each design is a subset of the eight locations that are to contain the components. From
Equation S2-4, the number of possible designs is

The following example uses the multiplication rule in combination with Equation S2-4 to an-
swer a more difficult, but common, question.

EXAMPLE S2-6 A bin of 50 manufactured parts contains three defective parts and 47 nondefective parts. A
sample of six parts is selected from the 50 parts. Selected parts are not replaced. That is, each
part can only be selected once and the sample is a subset of the 50 parts. How many different
samples are there of size six that contain exactly two defective parts?
A subset containing exactly two defective parts can be formed by first choosing the
two defective parts from the three defective parts. Using Equation S2-4, this step can be
completed in

a

3
2

b

3!
2! 1!

3 different ways

8!
5! 3!
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