Engineering Fundamentals: An Introduction to Engineering, 4th ed.c

(Steven Felgate) #1

274 Chapter 10 Force and Force-Related Parameters


Example 10.9 Starting with an atmospheric pressure of 101,325 Pa, express the magnitude of the pressure
in the following units: (a) millimeters of mercury ( mmHg), (b) inches of mercury (inHg),
(c) meters of water, and (d) feet of water. The densities of water and mercury are 
1,000 kg /m
3
and rHg13,550 kg /m
3
respectively.
(a) We start with the relationship between the height of a fluid column and the pressure
at the base of the column, which is

And solving forh, we have


Therefore, the pressure due to a standard atmosphere is equal to the pressure created at a base
of a 760-mm-tall column of mercury. Stated another way, 1 atm 760 mmHg.

h0.76 m760 mm


Prgh101,325a


N


m
2 b13,550a

kg


m
3 bc9.81a

m


s
2 bdh^1 m^2

rH
2 O

TABLE 10.4 Variation of Standard Atmosphere
with Altitude

Atmospheric Air Density
Altitude (m) Pressure (kPa) (kg /m

3


)


0 (sea level) 101.325 1.225
500 95.46 1.167
1000 89.87 1.112
1500 84.55 1.058
2000 79.50 1.006
2500 74.70 0.957
3000 70.11 0.909
3500 65.87 0.863
4000 61.66 0.819
4500 57.75 0.777
5000 54.05 0.736
6000 47.22 0.660
7000 41.11 0.590
8000 35.66 0.526
9000 30.80 0.467
10,000 26.50 0.413
11,000 22.70 0.365
12,000 19.40 0.312
13,000 16.58 0.266
14,000 14.17 0.228
15,000 12.11 0.195

Source:Data from U.S. Standard Atmosphere (1962).


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