Engineering Fundamentals: An Introduction to Engineering, 4th ed.c

(Steven Felgate) #1

614 Chapter 18 Mathematics in Engineering


Solutions of Simultaneous Linear Equations


As we discussed earlier, the formulation of many engineering problems leads to a system of
algebraic equations. As you will learn later in your math and engineering classes, there are a
number ways that we can use to solve a set of linear equations. In the section that follows, we
will discuss one of these methods that you can use to obtain solutions to a set of linear equations.

Gauss Elimination Method We will begin our discussion by demonstrating the Gauss elimination
method using an example. Consider the following three linear equations with three unknowns:
x 1 ,x 2 , andx 3.

(18.18a)


(18.18b)


(18.18c)


Step1: We begin by dividing the first equation, Equation (8.18a), by 2: the coefficient of the
x 1 term. This operation leads to

(18.19)


Step2: We multiply Equation (18.19) by 3: the coefficient ofx 1 in Equation (18.18b).


(18.20)


We then subtract Equation (18.20) from Equation (18.18b). This step will eliminatex 1
from Equation (18.18b). This operation leads to

(18.21)


Step 3: Similarly, to eliminatex 1 from Equation (18.18c), we multiply Equation (18.19) by 5:
the coefficient ofx 1 in Equation (18.18c).

(18.22)


We then subtract the above equation from Equation (18.18c), which will eliminatex 1
from Equation (18.18c). This operation leads to

(18.23)


a 5 x 1 


5


2


x 2 


5


2


x 3 


65


2


b





7


2


x 2 


1


2


x 3 


31


2


5 x 1 x 2  3 x 3  17


5 x 1 


5


2


x 2 


5


2


x 3 


65


2


a 3 x 1 


3


2


x 2 


3


2


x 3 


39


2


b


1


2


x 2 


5


2


x 3 


25


2


3 x 1  2 x 2  4 x 3  32


3 x 1 


3


2


x 2 


3


2


x 3 


39


2


x 1 


1


2


x 2 


1


2


x 3 


13


2


5 x 1 x 2  3 x 3  17


3 x 1  2 x 2  4 x 3  32


2 x 1 x 2 x 3  13


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