620 Chapter 18 Mathematics in Engineering
an important role in design of structures. We explained that, for a small area elementAlocated
at a distancexfrom the axisy–y, as shown in Figure 18.17, the area moment of inertia is
defined by
(18.31)
We also included more small area elements, as shown in Figure 18.18. The area moment
of inertia for the system of discrete areas shown about they–yaxis is now
Iyyx
2
A
(18.32)
Similarly, we can obtain the second moment of area for a cross-sectional area, such as a rect-
angle or a circle, by summing the area moment of inertia of all the little area elements that
makes up the cross-section. However, for a continuous cross-sectional area, we use integrals
instead of summing thex
2
Aterms to evaluate the area moment of inertia. After all, the integral
sign, , is nothing but a big “S” sign, indicating summation.
(18.33)
We can obtain the area moment of inertia of any geometric shape by performing the
integration given by Equation (18.33). For example, let us derive a formula for a rectangular
cross-section about they–yaxes.
step 1 step 2 step 3 step 4
Step 1: The second moment of the rectangular cross-sectional area is equal to the sum (inte-
gral) of little rectangles.
Step 2: We substitute fordAhdx(see Figure 18.19).
Step 3: We simplify by taking outh(constant) outside the integral.
Step 4: The solution. We will discuss the integration rules later.
Iyy
w /2
w /2
x
2
d A
w /2
w /2
x
2
hdxh
w /2
w /2
x
2
dx
1
12
hw
3
u u u u
Iyyx
2
d A
Iyyx
2
1 A 1 x
2
2 A 2 x
2
3 A 3
A 1
y
y
x 1
x 2 A 2
■Figure 18.18 x 3 A 3
Second moment of area for three
small area elements.
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