Higher Engineering Mathematics, Sixth Edition

(Nancy Kaufman) #1

Irregular areas, volumes and mean values of waveforms 209


50

Graph of power/time

40

30
Power (kW)
20

10

0 123456
Time (hours)

7.0 21.5 42.0 49.5 37.0 10.0

Figure 19.10


Area under curve=(width of interval)
×(sum of mid-ordinates)
=( 1 )[7. 0 + 21. 5 + 42. 0
+ 49. 5 + 37. 0 + 10 .0]
=167kWh(i.e. a measure
of electrical energy)

(b) Average value of waveform

=

area under curve
length of base

=

167kWh
6h
=27.83kW

Alternatively, average value

=

sum of mid-ordinates
number of mid-ordinates

Problem 8. Fig. 19.11 shows a sinusoidal output
voltage of a full-wave rectifier. Determine, using
the mid-ordinate rule with 6 intervals, the mean
output voltage.

10

0 308608908 1808 3608 

2

2708

Voltage (V)

 3 
2

2 

Figure 19.11

Onecycleoftheoutputvoltageiscompletedinπradians
or 180◦. The base is divided into 6 intervals, each of
width 30◦. The mid-ordinate of each interval will lie at
15 ◦,45◦,75◦,etc.
At 15◦ the height of the mid-ordinate is
10sin15◦= 2 .588V.
At 45◦ the height of the mid-ordinate is
10sin45◦= 7 .071V, and so on.
The results are tabulated below:

Mid-ordinate Height of mid-ordinate

15 ◦ 10sin15◦= 2 .588V

45 ◦ 10sin45◦= 7 .071V

75 ◦ 10sin75◦= 9 .659V
105 ◦ 10sin105◦= 9 .659V

135 ◦ 10sin135◦= 7 .071V

165 ◦ 10sin165◦= 2 .588V
sum of mid-ordinates=38.636V

Mean or average value of output voltage

=

sum of mid-ordinates
number of mid-ordinates

=

38. 636
6
=6.439V
(With a larger number of intervals a more accurate
answer may be obtained.) For a sine wave the actual
mean value is 0.637×maximum value, which in this
problem gives 6.37V.

Problem 9. An indicator diagram for a steam
engine is shown in Fig. 19.12. The base line has
been divided into 6 equally spaced intervals and the
lengths of the 7 ordinates measured with the results
shown in centimetres. Determine (a) the area of the
indicator diagram using Simpson’s rule, and (b) the
mean pressure in the cylinder given that 1cm
represents 100kPa.

12.0 cm

3.6 4.0 3.5 2.9 2.2 1.7 1.6

Figure 19.12
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