210 Higher Engineering Mathematics
(a) The width of each interval is
12. 0
6
cm. Using
Simpson’s rule,
area=^13 ( 2. 0 )[( 3. 6 + 1. 6 )+ 4 ( 4. 0
+ 2. 9 + 1. 7 )+ 2 ( 3. 5 + 2. 2 )]
=^23 [5. 2 + 34. 4 + 11 .4]
=34cm^2
(b) Mean height of ordinates
=
area of diagram
length of base
=
34
12
= 2 .83cm
Since 1cm represents 100kPa, the mean pressure
in the cylinder
= 2 .83cm×100kPa/cm=283kPa.
Now try the following exercise
Exercise 84 Further problems on mean or
average values of waveforms
- Determine the mean value of the periodic
waveforms shown in Fig. 19.13 over a half
cycle. [(a) 2A (b) 50V (c) 2.5A]
(^01020)
22
2
Current (A)
t (ms)
0510
2100
100
Voltage (V)
t (ms)
(a)
(b)
Figure 19.13
015 30
25
5
Current (A)
t (ms)
(c)
Figure 19.13 (Continued)
- Find the average value of the periodic wave-
forms shown in Fig. 19.14 over one complete
cycle. [(a) 2.5V (b) 3A]
(b)
0
5
Current (A)
(a)
(^0246810)
10
Voltage (mV)
t (ms)
246810 t (ms)
Figure 19.14
- Analternatingcurrent hasthefollowingvalues
at equal intervals of 5ms
Time(ms) 0 5 10 15 20 25 30
Current(A) 0 0.9 2.6 4.9 5.8 3.5 0
Plot a graph of current against time and esti-
mate the area under the curve over the 30ms
period using the mid-ordinate rule and deter-
mine its mean value.
[0.093As, 3.1A]
- Determine, using an approximate method, the
average value of a sine wave of maximum
value 50V for (a) a half cycle and (b) a
complete cycle. [(a) 31.83V (b) 0]