The solution of simultaneous equations by matrices and determinants 243
⎛
⎝
100
010
001
⎞
⎠×
⎛
⎝
x
y
z
⎞
⎠=
1
35
×
⎛
⎝
( 14 × 4 )+( 0 × 33 )+( 7 × 2 )
( 16 × 4 )+((− 5 )× 33 )+((− 2 )× 2 )
( 5 × 4 )+( 5 × 33 )+((− 5 )× 2 )
⎞
⎠
⎛
⎝
x
y
z
⎞
⎠=^1
35
⎛
⎝
( 14 × 4 )+( 0 × 33 )+( 7 × 2 )
( 16 × 4 )+((− 5 )× 33 )+((− 2 )× 2 )
( 5 × 4 )+( 5 × 33 )+((− 5 )× 2 )
⎞
⎠
=
1
35
⎛
⎝
70
− 105
175
⎞
⎠
=
⎛
⎝
2
− 3
5
⎞
⎠
(v) By comparing corresponding elements, x= 2 ,
y=− 3 , z= 5 , which can be checked in the
original equations.
Now try the following exercise
Exercise 98 Further problems on solving
simultaneous equations using matrices
In Problems 1 to 5 usematrices to solve the
simultaneous equations given.
- 3x+ 4 y= 0
2 x+ 5 y+ 7 =0[x= 4 ,y=−3] - 2p+ 5 q+ 14. 6 = 0
3. 1 p+ 1. 7 q+ 2. 06 = 0
[p= 1. 2 ,q=− 3 .4] - x+ 2 y+ 3 z= 5
2 x− 3 y−z= 3
− 3 x+ 4 y+ 5 z= 3
[x= 1 ,y=− 1 ,z=2] - 3 a+ 4 b− 3 c= 2
− 2 a+ 2 b+ 2 c= 15
7 a− 5 b+ 4 c= 26
[a= 2. 5 ,b= 3. 5 ,c= 6 .5] - p+ 2 q+ 3 r+ 7. 8 = 0
2 p+ 5 q−r− 1. 4 = 0
5 p−q+ 7 r− 3. 5 = 0
[p= 4. 1 ,q=− 1. 9 ,r=− 2 .7]
6. In two closed loops of an electrical circuit, the
currents flowingare givenby the simultaneous
equations:
I 1 + 2 I 2 + 4 = 0
5 I 1 + 3 I 2 − 1 = 0
Use matrices to solve forI 1 andI 2.
[I 1 =2,I 2 =−3]
7. The relationship between the displacement,s,
velocity,v, and acceleration,a, of a piston is
given by the equations:
s+ 2 v+ 2 a= 4
3 s−v+ 4 a= 25
3 s+ 2 v−a=− 4
Use matrices to determine the values ofs,v
anda.
[s= 2 ,v=− 3 ,a=4] - In a mechanical system, acceleration x ̈,
velocityx ̇and distancexare related by the
simultaneous equations: - 4 x ̈+ 7. 0 x ̇− 13. 2 x=− 11. 39
− 6. 0 x ̈+ 4. 0 x ̇+ 3. 5 x= 4. 98 - 7 x ̈+ 6. 0 x ̇+ 7. 1 x= 15. 91
Use matrices to find the values ofx ̈,x ̇andx.
[x ̈= 0 .5,x ̇= 0 .77,x= 1 .4]
23.2 Solution of simultaneous
equations by determinants
(a) When solving linear simultaneous equations in
two unknowns using determinants:
(i) write the equations in the form
a 1 x+b 1 y+c 1 = 0
a 2 x+b 2 y+c 2 = 0
and then
(ii) the solution is given by
x
Dx
=
−y
Dy
=
1
D
where Dx=
∣
∣
∣
∣
∣
b 1 c 1
b 2 c 2
∣
∣
∣
∣
∣
i.e. the determinant of the coefficients left
when thex-column is covered up,