Higher Engineering Mathematics, Sixth Edition

(Nancy Kaufman) #1

The solution of simultaneous equations by matrices and determinants 243




100
010
001


⎠×



x
y
z


⎠=
1
35

×



( 14 × 4 )+( 0 × 33 )+( 7 × 2 )
( 16 × 4 )+((− 5 )× 33 )+((− 2 )× 2 )
( 5 × 4 )+( 5 × 33 )+((− 5 )× 2 )





x
y
z


⎠=^1
35



( 14 × 4 )+( 0 × 33 )+( 7 × 2 )
( 16 × 4 )+((− 5 )× 33 )+((− 2 )× 2 )
( 5 × 4 )+( 5 × 33 )+((− 5 )× 2 )



=

1
35



70
− 105
175



=



2
− 3
5



(v) By comparing corresponding elements, x= 2 ,
y=− 3 , z= 5 , which can be checked in the
original equations.

Now try the following exercise


Exercise 98 Further problems on solving
simultaneous equations using matrices

In Problems 1 to 5 usematrices to solve the
simultaneous equations given.


  1. 3x+ 4 y= 0
    2 x+ 5 y+ 7 =0[x= 4 ,y=−3]

  2. 2p+ 5 q+ 14. 6 = 0
    3. 1 p+ 1. 7 q+ 2. 06 = 0
    [p= 1. 2 ,q=− 3 .4]

  3. x+ 2 y+ 3 z= 5
    2 x− 3 y−z= 3
    − 3 x+ 4 y+ 5 z= 3
    [x= 1 ,y=− 1 ,z=2]

  4. 3 a+ 4 b− 3 c= 2
    − 2 a+ 2 b+ 2 c= 15
    7 a− 5 b+ 4 c= 26
    [a= 2. 5 ,b= 3. 5 ,c= 6 .5]

  5. p+ 2 q+ 3 r+ 7. 8 = 0
    2 p+ 5 q−r− 1. 4 = 0
    5 p−q+ 7 r− 3. 5 = 0
    [p= 4. 1 ,q=− 1. 9 ,r=− 2 .7]
    6. In two closed loops of an electrical circuit, the
    currents flowingare givenby the simultaneous
    equations:
    I 1 + 2 I 2 + 4 = 0
    5 I 1 + 3 I 2 − 1 = 0
    Use matrices to solve forI 1 andI 2.
    [I 1 =2,I 2 =−3]
    7. The relationship between the displacement,s,
    velocity,v, and acceleration,a, of a piston is
    given by the equations:
    s+ 2 v+ 2 a= 4
    3 s−v+ 4 a= 25
    3 s+ 2 v−a=− 4
    Use matrices to determine the values ofs,v
    anda.
    [s= 2 ,v=− 3 ,a=4]

  6. In a mechanical system, acceleration x ̈,
    velocityx ̇and distancexare related by the
    simultaneous equations:

  7. 4 x ̈+ 7. 0 x ̇− 13. 2 x=− 11. 39
    − 6. 0 x ̈+ 4. 0 x ̇+ 3. 5 x= 4. 98

  8. 7 x ̈+ 6. 0 x ̇+ 7. 1 x= 15. 91
    Use matrices to find the values ofx ̈,x ̇andx.
    [x ̈= 0 .5,x ̇= 0 .77,x= 1 .4]


23.2 Solution of simultaneous


equations by determinants


(a) When solving linear simultaneous equations in
two unknowns using determinants:
(i) write the equations in the form
a 1 x+b 1 y+c 1 = 0
a 2 x+b 2 y+c 2 = 0
and then
(ii) the solution is given by

x
Dx

=

−y
Dy

=

1
D

where Dx=






b 1 c 1
b 2 c 2






i.e. the determinant of the coefficients left
when thex-column is covered up,
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