Higher Engineering Mathematics, Sixth Edition

(Nancy Kaufman) #1

Vectors 253


(ii) A lineabis constructed which is parallel to and
equal in length to 0 c.
(iii) The resultant force is given by the diagonal of the
parallelogram, i.e. length 0 b.

This procedure is called the ‘parallelogram’ method.


0

c

F 1

F 2

a

b



Figure 24.5


Problem 1. A force of 5N is inclined at an angle
of 45◦to a second force of 8N, both forces acting at
a point. Find the magnitude of the resultant of these
two forces and the direction of the resultant with
respect to the 8N force by:
(a) the ‘nose-to-tail’ method, and (b) the
‘parallelogram’ method.

The two forces are shown in Fig. 24.6. (Although the
8N force is shown horizontal, it could have been drawn
in any direction.)


458

5N

8N

Figure 24.6


(a) ‘Nose-to tail’ method


(i) The 8 N force is drawn horizontally 8 units long,
shown as 0 ain Fig. 24.7
(ii) From the nose of the 8N force, the 5N force
is drawn 5 units long at an angle of 45◦to the
horizontal, shown asab
(iii) The resultant force is given by length 0band
is measured as12Nand angleθis measured
as 17 ◦.

458

5N

8N a
0

b



Figure 24.7


(b) ‘Parallelogram’ method
(i) InFig. 24.8, a lineis constructed whichis parallel
to and equal in length to the 8N force
(ii) Alineisconstructedwhichisparalleltoandequal
in length to the 5N force
(iii) The resultant force is given by the diagonal
of the parallelogram, i.e. length 0b,andis
measured as 12Nand angle θ is measured
as 17 ◦.

458

5N

8N

b

0



Figure 24.8

Thus,theresultantofthetwoforcevectorsinFig.24.6
is 12N at 17◦to the 8N force.

Problem 2. Forces of 15N and 10N are at an
angle of 90◦to each other as shown in Fig. 24.9.
Find, by drawing, the magnitude of the resultant of
these two forces and the direction of the resultant
with respect to the 15N force.

15N

10N

Figure 24.9

Using the ‘nose-to-tail’ method:
(i) The 15N force is drawn horizontally 15 units
long as shown in Fig. 24.10
(ii) From the nose of the 15N force, the 10N force
is drawn 10 units long at an angle of 90◦to the
horizontal as shown
(iii) Theresultant forceis shown asRand is measured
as18Nand angleθis measured as 34 ◦.
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