Higher Engineering Mathematics, Sixth Edition

(Nancy Kaufman) #1

Standard integration 371


Problem 9. Determine
(a)


7sec^24 tdt (b) 3


cosec^22 θdθ.

(a) From Table 37.1(iv),

7sec^24 tdt=( 7 )

(
1
4

)
tan4t+c

=

7
4

tan4t+c

(b) From Table 37.1(v),

3


cosec^22 θdθ=( 3 )

(

1
2

)
cot2θ+c

=−

3
2

cot 2θ+c

Problem 10. Determine

(a)


5e^3 xdx (b)


2
3e^4 t

dt.

(a) From Table 37.1(viii),



5e^3 xdx=( 5 )

(
1
3

)
e^3 x+c=

5
3

e^3 x+c

(b)



2
3e^4 t

dt=


2
3

e−^4 tdt=

(
2
3

)(

1
4

)
e−^4 t+c

=−

1
6

e−^4 t+c=−

1
6e^4 t

+c

Problem 11. Determine

(a)


3
5 x

dx (b)

∫(
2 m^2 + 1
m

)
dm.

(a)



3
5 x

dx=

∫(
3
5

)(
1
x

)
dx=

3
5

lnx+c

(from Table 37.1(ix))

(b)


∫(
2 m^2 + 1
m

)
dm=

∫(
2 m^2
m

+

1
m

)
dm

=

∫(
2 m+

1
m

)
dm

=

2 m^2
2

+lnm+c

=m^2 +lnm+c

Now try the following exercise

Exercise 145 Further problems on standard
integrals
In Problems 1 to 12, determine the indefinite
integrals.


  1. (a)



4dx (b)


7 xdx

[
(a) 4x+c (b)

7 x^2
2

+c

]


  1. (a)



2
5

x^2 dx (b)


5
6

x^3 dx
[
(a)

2
15

x^3 +c (b)

5
24

x^4 +c

]


  1. (a)


∫(
3 x^2 − 5 x
x

)
dx (b)


( 2 +θ)^2 dθ





(a)

3 x^2
2

− 5 x+c

(b) 4θ+ 2 θ^2 +

θ^3
3

+c






  1. (a)



4
3 x^2

dx (b)


3
4 x^4

dx
[
(a)

− 4
3 x

+c (b)

− 1
4 x^3

+c

]


  1. (a) 2


∫√
x^3 dx (b)


1
4

√ 4
x^5 dx
[
(a)

4
5


x^5 +c (b)

1
9

√ (^4) x (^9) +c
]



  1. (a)



− 5

t^3

dt (b)


3
75


x^4

dx
[
(a)
10

t

+c (b)
15
7

√ (^5) x+c
]

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