Higher Engineering Mathematics, Sixth Edition

(Nancy Kaufman) #1

Chapter 40


Integration using


trigonometric and


hyperbolic substitutions


40.1 Introduction


Table 40.1 gives a summary of the integrals that require
theuse oftrigonometric and hyperbolic substitutions
and their application is demonstrated in Problems 1
to 27.


40.2 Worked problems on integration


ofsin^2 x,cos^2 x,tan^2 xandcot^2 x


Problem 1. Evaluate

∫ π
4
0

2cos^24 tdt.

Since cos2t=2cos^2 t−1 (from Chapter 17),


then cos^2 t=


1
2

( 1 +cos 2t)and

cos^24 t =

1
2

( 1 +cos 8t)

Hence


∫ π
4
0

2cos^24 tdt

= 2

∫ π
4
0

1
2

( 1 +cos 8t)dt

=

[
t+

sin8t
8


4
0

=




π
4

+

sin8


4

)

8



⎦−

[
0 +

sin0
8

]

=

π
4

or 0. 7854

Problem 2. Determine


sin^23 xdx.

Since cos2x= 1 −2sin^2 x(from Chapter 17),

then sin^2 x=

1
2

( 1 −cos 2x)and

sin^23 x =

1
2

( 1 −cos 6x)

Hence


sin^23 xdx=


1
2

( 1 −cos 6x)dx

=

1
2

(
x−

sin 6x
6

)
+c

Problem 3. Find 3


tan^24 xdx.

Since 1+tan^2 x=sec^2 x,thentan^2 x=sec^2 x−1and
tan^24 x=sec^24 x−1.

Hence 3


tan^24 xdx= 3


(sec^24 x− 1 )dx

= 3

(
tan 4x
4

−x

)
+c
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